Abag has 10 yellow poker chips and 4 green poker chips. if you reach in to randomly draw 5 chips, what is the probability of selecting exactly 3 yellow chips and 2 green chips?

In the study of probability, you find the chances of an event to happen likely out of the total number of possibilities. Thus, probabilities are always presented as part of a whole: in terms of fractions or percentages. 

In this problem, the denominator for the probability would be the total number of possibilities. In combination probability, we use the equation: n!/r!(n-r)!, where 'r' is the number of like things out of 'n' objects. So, the denominator would be 5 drawn chips out of a total of 14 chips. So,

denominator = 14!/5!(14-5)! = 2,002 ways

For the numerator, we multiply the combination for 3 out of 10 chips and 2 out of 4 chips. 

Numerator = 10!/3!(10-3)! × 4!/2!(4-2)!
Numerator = 720 ways

Thus, the probability is

Probability = 720/2002 = 360/1001 or 35.96%

Where is the rest of the question