One leg of a right triangle has a length of 55 m. the other sides have lengths that are consecutive integers. find these lengths.

First let us assign the variables for the two lengths:

x = 1st integer

x + 1 = 2nd consecutive integer = the hypotenuse of the right triangle

The 2nd consecutive integer should be the hypotenuse since its value should be highest among the three sides.

Now using the hypotenuse formula we calculate for x:

(x + 1)^2 = 5^2 + x^2

x^2 + 2x + 1 = 25 + x^2

2x + 1 = 25

2x = 24

x = 12 m

So other integer is

 x + 1 = 13 m

Therefore the other sides are 12 m and 13 m.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

answer: answer: d) v= 1/6 bh  

step-by-step explanation:

since according to the given question,   a pyramid is placed inside a prism.

step-by-step explanation: