Ralph is painting the barn below, including the sides and roof. he wants to know how much paint to purchase.

a.
what is the total surface area that he is going to be painting? round your answer to the nearest hundredth.
b.
if one paint can covers 57 square feet, how many paint cans should he purchase?
c.
if each paint can costs $23.50, how much will the paint cost?
d.
once the barn is finished being painted, there is going to be a party. ralph wants to know how many people to invite to the party. what is the volume of the inside of the barn?

someone me

PART A

The barn is constructed by the following 2D shapes

Two triangles of height = 4' and base = 20'
Area = 2 × (0.5×4×20) = 80

Two rectangles of length = 20' and width = 15'
Area = 2 × 20 × 15 = 600

Two rectangles of length = 45' and width = 15'
Area = 2 × 45' × 15' = 1350

One base of length = 45' and width = 15'
Area = 45 × 15 = 675

Two rectangles on each on one side of the roof. We have the length = 45'  but not the width. We can work out the width by using Pythagoras theorem

w² = 4² + 10²
w² = 16 + 100
w² = 116
w = √116 = 10.77

Area of the two rectangles on the roof part is = 2 ×10.77 × 45 = 969.33

Total area to paint = 969.33+675+1350+600+80 = 3674.33 ≈ 3700 (to the nearest hundreth)

PART B

Numbers of paint cans needed = 3700 ÷ 57 = 64.9 ≈ 65 cans

PART C

Total cost of paint = 65 × 23.50 = $1527.50

PART D

The barn is constructed by a cuboid and a rectangular prism

V of cuboid = length × width × height
V of cuboid = 20 × 45 × 15
V of cuboid = 13500

V of triangular prism = Area of cross section × depth
V = [0.5×4×20] × 45
V = 1800

Total volume = 1800 + 13500 = 15300

The first one minimumi hope my answer you.

The correct graph is the second one, with the points being at (-6,0), (2,0) and reaching down to (-2,-8)