The rectangular coordinates of a point are given. plot the point. (−4, 3) find two sets of polar coordinates for the point for 0 ≤ θ < 2π. (round your answers to four decimal places.)

 The polar coordinate of a point is in the form of:

polar coordinate: (r, θ)

where r is the resultant vector and θ is the angle from the x axis to the vector

We can solve for r using the hypotenuse formula:

r^2 = x^2 + y^2

r^2 = (- 4)^2 + (3)^2

r^2 = 16 + 9

r^2 = 25

r = ± 5

Using the tan function to find for θ:

tan θ = y / x

θ = tan^-1 (3 / -4)

θ = -36.8699 (clockwise from x axis)  or equivalent to θ = 360-36.8699 = 323.1301°

Since our other point lies on the 3rd quadrant (negative x, positive y) we add 180° to get the other angle:

θ = 180 – 36.8699

θ = 143.1301° (counterclockwise from x-axis)

Therefore the 2 sets of polar coordinates are:

(5, 323.1301°) and (-5, 143.1301°)

or in rad form:

(5, 1.8π) and (-5, 0.8π)

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate