Daily usage is exactly 60 gallons per day. lead time is normally distributed with a mean of 10 days and a standard deviation of 2 days. what is the standard deviation of demand during lead time? 60 times 10 60 times the square root of 10 60 times the square root of 2 10 times the square root of 2 60 times 2

We are told that the daily usage is exactly 60 gallons per day, therefore the total number of gallons that is used during the mean lead time is also called the mean demand amount:

Mean demand amount = Daily usage * Mean lead time

Mean demand amount = (60 gallons / day) * 10 days

Mean demand amount = 600 gallons

Since the standard deviation of the lead time is 2 days, therefore the standard deviation of the demand should also be:

Standard deviation of demand = Daily usage * Standard deviation of lead time

Standard deviation of demand = (60 gallons / day) * 2 days

Standard deviation of demand = 120 gallons

Short

60 times 2

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant