Apassword is 4 characters long, consisting of 2 letters and 2 numbers. the password must begin and end with a letter. if numbers can be repeated but letters cannot, how many possibilities are there? a. 65,000 b. 60,840 c. 58,500 d. 52,650

26 letters in the alphabet

 1st digit can be any letter so 26 possibilities

2nd digit is a number 0-9, so 10 possibilities

3rd digit is also 10 possibilities

 4th digit can be any letter except what the 1st digit is so 26-1 = 25 possibilities

26 x 10 x 10 x 25 = 65000 combinations

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11