In the game of blackjack, determine the odds of dealing yourself a blackjack (ace plus face-card or 10) from a single deck. show how you arrived at your answer.

There are 4 aces and 16 tens (10/J/Q/K of each suit). So there are (16*4= 64 ways to deal a blackjack with ace as first card and a ten as the second card- Ace/10. There are another 64 ways to deal it with a ten as the first card and the ace as the second card - 10/Ace. That's 128 first/second card combinations that are blackjacks.

There are  52 possibilities for the first card, 51 for the second for 2652 total possible first/second card combinations so the odds of dealing a blackjack are 128/2652, which reduces to 32/663 odds

The answer is the second choice

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !