Meg plotted the graph below to show the relationship between the temperature of her city and the number of people at a swimming pool: main title on the graph is swimming pool population. graph shows 0 to 30 on x axis at increments of 5 and 0 to 12 on y axis at increments of 1. the label on the x axis is temperature in degree c, and the label on the y axis is number of people at the pool. dots are made at the ordered pairs 2.5, 1 and 5, 2 and 7.5, 2 and 7.5, 3 and 7.5, 4 and 10, 5 and 10, 6 and 12.5, 6 and 15, 7 and 15, 8 and 17.5, 5 and 17.5, 7 and 20, 9 and 22.5, 7 and 22.5, 9 and 25, 11 and 27.5, 12. part a: in your own words, describe the relationship between the temperature of the city and the number of people at the swimming pool. (5 points) part b: describe how you can make the line of best fit. write the approximate slope and y-intercept of the line of best fit. show your work, including the points that you use to calculate slope and y-intercept. (5 points)

1. Plot your data in a graphing paper or excel.
2. Make sure that your plotted data has a solid mark to indicate the points in the graph.
3. Divide your data points by labeling x at the center, at the farthest part of your line (left or right diagonally).
4. If you feel that the data are now finely divided, then construct a line base on the x marks you're placing
5. Then you will notice how far or near your date points are by simply looking at the points near the constructed line that you created.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

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