How to go from sum of products to product of sums?

Multiplication gives us distribution over the products, so

(a′+b+d′) (a′+b+c′+f′) = a′ (a′+b+c′+f′) + b (a′+b+c′+f′) + d′ (a′+b+c′+f′)

And then you can then distribute again each of the factors on the right.

Then you should simplify in any given number of ways. To take as an example, you have a′b and ba′, and since a′b + a′b = a′b + a′b = a′b, you can just drop one of them. Since bb = b, you can rewrite bb as b and etc.

So in the end part we should arrive at a sum of products. Then you can just invert. For example, if at the end you had:

p′ = a′b + bc′ + d′f ′+ a′f′

Then we would have

p = p′′ = (a′b + bc′ + d′f′ + a′f′)′ = (a′b)′⋅(bc′)′⋅(d′f′)′⋅(a′f′)′

Then applying De Morgan's laws to each of the factors, e.g., (a′b)′ = a+b′, so we would have

p = (a+b′)⋅(b′+c)⋅(d+f)⋅(a+f)

which is a product of sums.

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.