All computers are on sale for 10% off the original price. if x is the original price of the computer, then the function that represents the price after only a 10% discount is: p(x) = x - 0.1x p(x) = 0.9x the function that gives the price, c, if only a $150 coupon is used is: c(x) = x - 150 choose the composition function that gives the final sale price after a 10% discount is followed by a $150 coupon

We are given the functions:

P (x) = 0.9 x

C (x) = x – 150

We can generate two composition functions from the given two functions in the form of:

P [C (x)]                and C [P (x)]

Since the problem states that we are to find for the final price after a 10% discount is followed by a $150 coupon then we should find for:

C [P (x)]

The value of C [P (x)] can obtained by plugging in the value of P (x) into x in the equation of C (x), therefore:

C [P (x)] = [0.9 x] – 150

C [P (x)] = 0.9 x – 150                      (ANSWER)

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204