The following statistics represent weekly salaries at a construction company.
mean $550. first quartile $480
median $630 third quartile $700
mode $605. 91st percentile $891
the most common salary is ?
the salary that half the employees salaries surpass is ?
the percent of employees salary that serve because $700 is ?
percent of employees salaries that were less than $480 is
the percent of employees salaries this surpass $891 years
if the company has 104 is the total weekly salary of all employees he is $?

i don't know how to solve the questions

The most common salary is $605. The salary that half the employees salaries surpass is $630. The percent of employees salary that serve because $700 is 75%. Percent of employees salaries that were less than $480 is 25%. The 9% percent of employees salaries this surpass $891 years. The total weekly salary of 104 employees is 57200.

Step-by-step explanation:

It is given that mean is $550, first quartile is $480,  median is $630, third quartile is $700,  mode is $605 and 91st percentile is $891.

First quartile is at 25% of the data, median is at 50% of the data, third quartile is at 75% of the data.

The mode of a set of data values is the value that occurs most often.

The most common salary is mode, therefore the most common salary is $605.

The salary that half the employees salaries surpass is $630. Because median is the half of the data.

The percent of employees salary that serve because $700 is 75%. Because $700 is third quartile.

Percent of employees salaries that were less than $480 is 25%. Because $480 is first quartile.

The percent of employees salaries this surpass $891 years is 9%. Because $891 is 91 percentile. Therefore 9% employees get more than $891.

If the company has 104 employees than the total salary of employees is

because means is $550, therefore the total weekly salary of 104 employees is 57200.

The most common salary is .

The salary that half the employees' salaries surpass is .

The percent of employees salary that serves because is %.

The percent of employees' salaries that were less than is %.

The % percent of employees' salaries surpass years.

The total weekly salary of employees is .

Given Mean is , the first quartile is .

The Median is , the third quartile is , the Mode is and the percentile is .

The first quartile is at % of the data, the median is at % of the data, the third quartile is at % of the data.

The mode of a set of data values is the value that occurs most often, So the most common salary is a mode, therefore the most common salary is .

As the median is half of the data, the salary that half of the employees' salaries surpass is .

Given that  is the third quartile, so the percent of employees ' salary that serves

The Percent of employees' salaries that were less than is % as  first quartile.

The percent of employees salaries this surpass $891 years is %. Because is percentile. Therefore more than .

If the company has employees then the total salary of employees is

because means is , therefore the total weekly salary of employees is .

Therefore, the most common salary is . The salary that half the employees' salaries surpass is . The percent of employees salary that serves because is %. The percent of employees' salaries that were less than is %.The % percent of employees' salaries surpass years and the total weekly salary of employees is .

Know more about the statistical analysis here:

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the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

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step-by-step explanation: