How many 3 person group can be formed in a club with 8 people?

Hi!

I'm going to make a text diagram.
Each | is a person.

| | | | | | | |

Now seperate into groups of three

| | |

| | |

| |

There are 2 groups of three

The answer is 2.

Hope this helps! :)

The first person in the group can be selected in any one of 8 ways. 
Once selected, the second person can be selected in any one of 7 ways. 
Once the first two are selected, the remaining person can be selected in any one of 6 ways. 

This can be done in a total of 8 x 7 x 6 ways. 

But, since the order in which the people appear in the group is not important, and since 3 people can be arranged in 3 x 2 x 1 = 6 ways, you need to divide the above number by 6 to filter out those groups with the same members (just rearranged). The answer is therefore, 

(8 x 7 x 6) / (3 x 2 x 1) = 56

Yes, two vertical lines can be complementary

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12