Afootball is thrown with an initial upward velocity of 25 feet per second from a height of 5 feet above the ground. the equation h = −16t^2 +25t + 5 models the height in feet t seconds after it is thrown. after the ball passes its maximum height, it comes down and hits the ground. about how long after it was thrown does it hit the ground?

A = -16
B = 25
C = 5

Plug into the quadratic equation and you get: -0.18 and 1.75. Since we cannot have a negative time our answer is 1.75 seconds.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12