What set of transformations is performed on lmno to form l′m′n′o′? a coordinate grid is shown from positive 6 to negative 6 on the x-axis and from positive 6 to negative 6 on the y-axis. a polygon lmno is shown with vertex l on ordered pair 2, negative 2, vertex m on ordered pair 4, negative 2, vertex n on ordered pair 5, negative 3 and vertex o on ordered pair 1, negative 3. a polygon l prime, m prime n prime o prime with vertex l prime on ordered pair negative 3, negative 2, m prime on negative 3, negative 4, n prime on negative 4, negative 5 and o prime on negative 4, negative 1. a 90 degrees counterclockwise rotation about the origin followed by a translation 1 unit to the left a 270 degrees counterclockwise rotation about the origin followed by a translation 1 unit to the left a translation 1 unit to the left followed by a 270 degrees counterclockwise rotation about the origin a translation 1 unit to the left followed by a 90 degrees counterclockwise rotation about the origin

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.