How many terms are in the polynomial abcd + e - h 2? two three five six

The number of terms in the polynomial are:

Three.

Step-by-step explanation:

We are given a polynomial expression in terms of variable a,b,c,d , e and h as:

We know that in any algebraic expression the number of terms are the number of unlike expressions that are separated by a minus or plus i.e. addition sign.

Hence here by looking at our polynomial expression we see that there are three terms in the expression :

                 1)  

                 2)  

                 3)    

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.