Three dressers are placed side by side. one dresser is 6 feet 7 inches wide, another is 2 feet 10 inches wide, and the third is 2 feet 8 inches wide. how wide are they combined?

1 foot = 12 inches

 dresser 1 = 6 ft 7 inches

 dresser 2 = 2 ft 10 inches

dresser 3 = 2 ft 8 inches

6 +2 +2 = 10 feet

7+10+8=25 inches

25/12 = 2 feet 1 inch

10 +2 = 12 feet plus 1 inch

 total width = 12 feet 1 inch

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

c.)

step-by-step explanation: