Use the student's t distribution to find tc for a 0.95 confidence level when the sample is 29. (round your answer to three decimal places.)

As we are using confidence level. So we are applying a two tailed test.
As given in question confidence level is 0.95.
So two tailed alpha is = 100 - 0.95 = 0.05
One tailed alpha = (two tailed alpha) / 2 =0.05/2  = 0.025

Sample space = 29
So degree of freedom(DF) = N - 1 (Where N = degree of freedom)
So DF = 29 - 1 = 28
So we will use Row DF  = 28
Use column alpha = 0.05(two tailed) = 0.025(one tailed.)

So tc for confidence level 0.95 and sample 29 is = 2.048
(from t value chart)