If the discriminant of an equation is negative, which of the following is true of the equation

a it has two complex solutions
b it has one real solution
c it had two real solutions

A. It has two complex roots.

Step-by-step explanation:

We are given that

Discriminant of an equation =negative

We have to find which is  true about the equation .

Let quadratic equation

Discriminant=

If D < 0 , then the equation has complex roots.

Therefore, if the discriminant of an equation is negative then the equation has two complex roots.

A. It has two complex roots.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3