Which answer does not correctly describe the graph of y = 5x + 12?

the answer choices are 1. the line has a constant rate of change 2. the graph contains the point (5, 12) 3. the line crosses the y-axis 12 units above the origin 4. the slope of the line can be written as 5/1

2. The Graph Contains The Point (5, 12)

Remember that in a linear function of the form , is the slope/rate of change of the line and is the y-intercept.

From our equation we can infer that , so the y-intercept of our graph is 12 units above the origin on the point (0, 12). Therefore, choice 2 correctly describe the graph of y = 5x + 12

We can also infer that , so the slope of our line is 5, which is constant, so our line has a constant rate of change. Also, since every integer can be written as a fraction with denominator 1, we can write our slope as . Therefore, choices 1 and 2 correctly describe the graph of y = 5x + 12.

Now, remember that any point on the plane has coordinates , so, to check if a point is on a line, we just need to replace the and values in the line equation and check if the equation holds. Our point is (5, 12), so x = 5 and y = 12. Lets replace the values in our line:

Since the equation equation doesn't hold (12 is not equal 37), we can conclude that the graph doesn't contain the point (5, 12). Therefore, choice 2 does NOT correctly describe the graph y = 5x +12.

The graph contains the point (5,12)

I got it right on t t m

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8