In a class of 30 students, everyone has either a pierced nose or a pierced ear. the professor asks everyone with a pierced nose to raise his or her hand. eight hands go up. then the professor asked everyone with a pierced ear to do likewise. this time there are 25 hands raised. how many students have piercings both on their ears and their noses?

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: