Evaluate the function rule to find the range of each function for the domain {-3, 0, 5}. f(x) = x² − 6x + 4
a. {-5, -4, -1}
b. {-5, -1, 4}
c. {-1, 4, 31}
d. {4, 31, 59}

i beg of you!

The range is the set of images; so, as you have the domain set and the function rule, you just have to calculate the value of the function for each value of the domain:

Domain        image, f(x) =x^2 - 6x + 4

-3                (-3)^2 - 6(-3) + 4 = 9 + 18 + 4 = 31

0                 (0)^2 - 6(0) + 4 = 0 - 0 + 4 = 4

5                  (5)^2 - 6(5) + 4 = 25 - 30 + 4 = - 1

So, we got the images -1, 4, and 31 and that is that is the range {-1, 4, 31}

option C. {-1, 4 , 31}

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5