Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial function. f(x) = 3(4)(2x-4) h(x) = (x + 2)3 + 1

F(x) = 2^x; h(x) = x^3 + x + 8

Table

x      f(x) =  2^x             h(x) = x^3 + x + 8

0      2^0 = 1                0  + 0 + 8 = 8

1     2^1 = 2                 1^3 + 1 + 8 = 10

2      2^2 = 4                2^3 + 2 + 8 = 8 + 2 + 8 = 18

3      2^3 = 8                3^3  + 3 + 8 = 27 + 3 + 8 = 38

4      2^2 = 16              4^3 + 4 + 8 = 76

10    2^10 = 1024       10^3  +10 + 8 = 1018

 9      2^9 =   512        9^3 + 9 + 8 = 729 + 9 + 8 = 746 

an approximate value of 10

Same length is comparing because it’s saying its the same and not different

Just tell koda to adjust the number of shapes himself.