An anthropologist finds bone that her instruments measure it as 0.601% of the amount of carbon-14 the bones would have contained when the person was alive. how long ago did the person die? the half life of carbon 14 is 5,730 years. round your answer to the nearest thousand.

To solve this problem, let us first calculate the rate constant, k .Assuming the decay of C-14 is of 1st order reaction, the formula for half-life is given as:

t-half life = ln 2 / k

where k = rate constant of decay

5730 = ln 2 / k

k = 1.21 * 10^-4

The rate equation for a 1st order reaction is given as:

ln (A / Ao) = - k t

Where A = final amount of C-14, and Ao = initial amount of C-14

Since A = 0.00601 Ao therefore,

ln (0.00601) = - 1.21 * 10^-4 * t

t = 42,278.34 years

The person died around 42,278 years ago.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

y + 11 = (1/4)(x + 16)

step-by-step explanation: