Mathematics, 13.11.2019 08:31 Robinlynn228
The absolute value function g(x) = |x + 7| − 4 is translated 5 units right and 2 units up to become g′(x). the quadratic function f(x), graphed below, is also moved 5 units right and 2 units up to become f′(x). which of these two transformed functions has a range of y ≤ −2 and what is the vertex of this transformed function?
g′(x) has a range of y ≤ −2 and its vertex is at (−2, −2).
g′(x) has a range of y ≤ −2 and its vertex is at (2, −2).
f′(x) has a range of y ≤ −2 and its vertex is at (3, −2).
f′(x) has a range of y ≤ −2 and its vertex is at (−7, −6).
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The absolute value function g(x) = |x + 7| − 4 is translated 5 units right and 2 units up to become...
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