Jeff invested $3000 in an account that earns 6.5% interest, compounded annually. the formula for compound interest is a=p(1+i)t .

how much did jeff have in the account after 3 years ?

a. $13,476.38
b. $3623.85
c. $3390.00
d. $9585.00

Option B - $3623.85

Step-by-step explanation:

Given : Jeff invested $3000 in an account that earns 6.5% interest, compounded annually. The formula for compound interest is  .

To find : How much did Jeff have in the account after 3 years ?

Solution :

The formula for compound interest is .

Where A is the amount

P is the principal = $3000

I is the interest = 6.5%=0.065

t is the time = 3 years

Substitute in the formula,

Therefore, Option B is correct.

The amount Jeff have in the account is $3623.85

y=mx+b

step-by-step explanation:

m slope

b y-intercept

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.