Which line contains the point (1,-3)

There are infinitely many lines that have the point (1,-3).

A line can be expressed as:

y=mx+b, where m=slope and b=y-intercept..

Our only restriction is that it passes through (1,-3) so

-3=1m+b

So as long as the sum of the slope and the y-intercept is equal to -3, that is one of the infinite number of lines that passes through (1, -3)

So we could also say b=-3-m then our infinite lines are:

y=mx-3-m, now any real value of m creates a specific line that passes through the point. ie the first few are

y=x-4, y=2x-5, y=3x-6 or even y=x√2-3-√2