If ef = hg and hg = 16, find the diameter of k

Diameter of the circle K = 20 units

Step-by-step explanation:

Given that : EF = HG

Also, HG = 16 units

⇒ EF = 16 units

Now, any line drawn perpendicular to the chord always bisects the chord

⇒ KI will bisect the chord EF

⇒ EI = 8 units

Now, in ΔEIK using Pythagoras theorem we have :

⇒ EK² = 8² + 6²

⇒ EK² = 100

⇒ EK = 10 units

So, Radius of the circle K = 10 units

Now, Diameter of the circle K = 2 × 10

                                                  = 20 units

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

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step-by-step explanation: