Mrs. ming invested an amount of money in two accounts for one year. she invested some at 8% interest and the rest at 6% interest. her total amount invested was $1,500. at the end of the year, she had earned $106.40 in interest. how much had mrs. ming invested in the account paying 6%?
a.$117
b.$680
c.$760
d.$820

The correct option is B.

Step-by-step explanation:

It is given that Mrs. Ming invested an amount of money in two accounts for one year.She invested some at 8% interest and the rest at 6% interest. Her total amount invested was $1,500.

Let the amount invested in the account paying 6% be x. So, the amount invested in the account paying 8% is 1500-x.

Total interest earned by Ming is

At the end of the year, she had earned $106.40 in interest.

Divide both sides by -2.

The value of x is 680, therefore the amount invested in the account paying 6% is 680 and the correct option is B.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)