Ahypotenuse of a right triangle is 52 in. one leg of the triangle is 8in. more than twice the length of the other. what is the perimeter of the triangle?

c=52, a=2b+8

Pythagorean Theorem = a^2+b^2=c^2

(2b+8)^2+b^2=52^2

4b^2+32b+64+b^2=2704

5b^2+32b-2640=0

b=20

a= 2(20)+8 = 48

48+20+52 = 120

i dont get it. where are the "descriptions"?

your answer is b ^w^ hope i