Mathematics, 15.10.2019 04:30 mdngndntbdnbd

The work of a student to solve the equation 2(6y − 3) = 20 + 6y is shown below:

step 1: 2(6y − 3) = 20 + 6y
step 2: 8y − 5 = 20 + 6y
step 3: 2y − 5 = 20
step 4: 2y = 25
step 5: y = 12.5

in which step did the student first make an error and what is the correct step?

step 2: 8y − 5 = 10 + 3y
step 2: 12y − 6 = 20 + 6y
step 3: 6y − 3 = 2(18 + 3y)
step 3: 2(6y − 3) = 18 + 3y

Answers: 3

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The work of a student to solve the equation 2(6y − 3) = 20 + 6y is shown below:

step 1:...