The work of a student to solve the equation 2(6y − 3) = 20 + 6y is shown below:

step 1: 2(6y − 3) = 20 + 6y
step 2: 8y − 5 = 20 + 6y
step 3: 2y − 5 = 20
step 4: 2y = 25
step 5: y = 12.5

in which step did the student first make an error and what is the correct step?

step 2: 8y − 5 = 10 + 3y
step 2: 12y − 6 = 20 + 6y
step 3: 6y − 3 = 2(18 + 3y)
step 3: 2(6y − 3) = 18 + 3y

2(6y − 3) = 20 + 6y

Use the distributive property, which states a(b - c) = ab - ac

We should get:

2*6y - 2*3 = 20 + 6y

Which can be simplified to:

12y - 6 = 20 + 6y

That means the mistake was in step 2. The student didn't multiply the numbers and instead added the numbers.

Your answer is: Step 2: 12y-6=20+6y

the answer is d. (1.2, -4.7) on edgn

hope this !

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.