According to government data, the probability that a woman between the ages of 25 and 29 was never married is 40%. in a random survey of 10 women in this age group, what is the probability that at least eight were married?

This is a case of binomial distribution. The formula used in calculations for binomial probability is:

P = nCr p^r (1-p)^(n-r) 

Where,

P = probability

nCr = combinations of r from n possibilities

p = success rate = 40% = 0.40

n = sample size = 10

1st: Let us calculate for nCr for r = 8 to 10. Formula is:

nCr = n! / r! (n-r)! 

10C8 = 10! / 8! 2! = 45

10C9 = 10! / 9! 1! = 10

10C10 = 10! / 10! 0! = 1

Calculating for probabilities when r = 8 to 10:

P (r=8) = 45 * 0.4^8 (0.6)^2 = 0.0106

P (r=9) = 10 * 0.4^9 (0.6)^1 = 0.0016

P (r=10) = 1 * 0.4^10 (0.6)^0 = 0.0001

Total probability that at least 8 were married = 0.0106 + 0.0016 + 0.0001

Total probability that at least 8 were married = 0.0123

y-1700=200(x+4)

step-by-step explanation:

200(x+4) is 200x + 800 she is saving 200 per week x is the weeks and the -1700 is. us that’s howmuch she already had

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d