Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the parameter. x = 6 + ln(t), y = t2 + 2, (6, 3)

Point a is located at (0, 4), and point c is located at (−3, 5). find the x value for the point b that is located one fourth the distance from point a to point c. −0.25 −0.5 −0.75 −1

For f(x)=2x+3 and g(x)=x^2- 8 find (f+g) (x)

Reflect the point (7,0) across the y-axis