ANSWER
The correct answer is option A.
![B(2)= - 1](/tpl/images/0335/4659/1d517.png)
EXPLANATION
Given that
![B](/tpl/images/0335/4659/ee024.png)
is a function of
![x](/tpl/images/0335/4659/a0e3f.png)
,
then we can write the point,
![(x,y)](/tpl/images/0335/4659/a46a1.png)
as
![(x,B(x))](/tpl/images/0335/4659/b8a6c.png)
![B(2)](/tpl/images/0335/4659/2c2cf.png)
is just the y-value of point that has an x-coordinate of
![2](/tpl/images/0335/4659/05229.png)
From the grid, each of the boxes is 1 unit.
This means that, when we count 2 units to the right, we will get
![x = 2](/tpl/images/0335/4659/53319.png)
If we move down one unit, we get the point with coordinates
![(2,-1)](/tpl/images/0335/4659/bd9a5.png)
This means that
![B(2)= - 1](/tpl/images/0335/4659/1d517.png)
see attachment.
![The graph of the function b is shown below. find b(2). a. -1 b. 1 c. 2](/tpl/images/0335/4659/8688c.jpg)