If line ji is a midsegment of triangle fgh, find hg. all measurements in the diagram are in inches.

Length of segment HG=60 inches.

Length of JI=30 inches.

Step-by-step explanation:

Given , if a line JI is a midsegment of triangle FGH.

Triangle midsegment theorem: It states that when a segment formed by joining of midpoints of any two sides of a triangle then it is parallel to III side of triangle and half of its length.

JI is the midsegment , J is the midpoint of side HF and I is the midpoint of GF

Therefore, we have

HJ=JF and GI=IF

2x-3=x+2

By subtracting property of equality

2x-x=2+3

x=5 ( by simplification)

Length of side HG= 11x+5

Length of side HG= inches.

By substituting the value of x

JI=

By using theorem

JI=

JI=30 inches.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: