From a boat on the lake, the angle of elevation to the top of a cliff is 26°1'. if the base of the cliff is 205 feet from the boat, how high is the cliff (to the nearest foot)?

Let the distance of the cliff from the boat be y and height of the top of the cliff be x.

As per the statement:

From a boat on the lake, the angle of elevation to the top of a cliff is 26°1'. If the base of the cliff is 205 feet from the boat.

⇒y = 205 feet,

We have to find the high is the cliff i,e x.

Using tangent ratio:

See the diagram as shown below:

Opposite side = x feet

adjacent side = 205 feet

Using conversion:

then;

Substitute these values we have;

Multiply both sides by 205 we have;

ft

Therefore, 100 ft high is the cliff(to the nearest foot)

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.

we can set up an equation to find the girls' ages. the equation is         28=0.5x-5+x. (comment if you need me to explain how i got this equation.) so, you add x and 0.5x to get 1.5x and add 5 to each side. your new equation is 33=1.5x. now divide both sides of the equation by 1.5 to get 22=x. because x is mary's age, to find jasmine's age we subtract mary's age from 28. we find that mary is 22 years old and jasmine is 6 years old.