Aparticle is moving along the parabola x^2=4(y+6). as the particle passes through the point (8,10), the rate of change of its y-coordinate is 5 units per second. how fast, in units per second, is the x-coordinate changing at this instant?

You'll need to use differentiation (specifically, implicit differentiation) here.

If x^2 = 4(y+6), differentiating both sides with respect to time t produces the following:

2x (dx/dt) = 4([dy/dt])   (note that (d/dt) 6 = 0)

We need to solve for (dx/dt).  Substitute 8 for x (y does not appear in this latest equation, so we do nothing with y=10).  Substitute the given 5 units/sec for dy/dt:

2(8)(dx/dt) = 4(5)(units/sec)

Solving for dx/dt, dx/dt = [20 units/sec]/16, or 5/4 units/sec, or 1.25 units/sec.

It will take him 5 days

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%