There are 2,000 eligible voters in a precinct. 500 of the voters are randomly selected and asked whether they planned to vote for the democratic incumbent or the republican challenger. of the 500 surveyed, 350 said they would vote for the democratic incumbent. using the 0.99 confidence coefficient, what are the confidence limits for the proportion that plan to vote for the democratic incumbent?

99% confidence limits for population proportion is:

CL = P +- Z * √(P*(1-P)/N))

Where:

P = sample proportion

Z = Z-score taken at 99% confidence = 2.575

N = sample size

Calculating for the values:
P = 350/500 = 0.7 
N = 500 

Substituting know values to the CL equation:

CL = 0.7 +-  2.575* √(0.7*(1-0.7)/500))

CL = 0.647 , 0.753

Therefore confidence limits range from 0.647 to 0.753.

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb