Point p lies on the line with the equation y-4=3(x-2). if the x-coordinate of p is 4, what is the y-coordinate of p

Let's start by tidying up that equation and put it into slope-intercept form (y = mx + b); from there, we can plug in coordinates.



Let's use the distributive property on the right side:


Now add 4 to both sides


Which simplifies to:


Since that's the equation of our line, now we can plug in coordinates and see what it churns out. 

We know that the x-coordinate of P = 4 so let's substitute 4 in for x and calculate the y-coordinate:





So the y-coordinate for point P = 10