Mathematics, 12.10.2019 00:00 Kurlyash

Suppose a and b are independent events. if p(a)=0.2 and p(b)=0.6, what is p(a^b)?

a 0.2
b 0.12
c 0.08
d 0.6

Answers: 1

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Answer from: kbows12

OK so you want the probabilty of A and B occurring. Independet event probabilities are multiplied so its 0.2 * 0.6 = 0.12

b

Answer from: pjgolden04

$P(A\cap B)=0.12$

Step-by-step explanation:

We know that if two events M and N are independent, then the probability of the intersection of the two events is given by :-

$P(M\cap N)=P(M)\times P(N)$

Given: The events A and B are independent .

Therefore, $P(A\cap B)=P(A)\times P(B)$

If P(A)=0.2 and P(B)=0.6

Then,

$P(A\cap B)=0.2\times 0.6\\\\\Rightarrow P(A\cap B)=0.12$

Answer from: Quest

All about the same size in the city the game was

Answer from: Quest

answer: the proof is mentioned below.

step-by-step explanation:

since, given: lines bc = ef

prove: lines ac > ef

statements reason

1. bc=ef 1. given

2. ac= ab+bc 2. because b is the point between the

line segment ac

3. ac > bc 3. because if a line segment is equal to

the sum of two line segments then it is

always greater then each of these

individual line segments

4. ac > ef 4. by equality property.

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Suppose a and b are independent events. if p(a)=0.2 and p(b)=0.6, what is p(a^b)?

a 0.2...