Acylindrical carbored for tube with a diameter of 8 cm and a height of 20 cm is used to package a gift what is the approximate volume of youtube round to the nearest whole cubic centimeter?

volume for a cylinder is PI * r^2 * h

 so using 3.14 for PI since you don't say what value to use

volume = 3.14 x 4^2 x 20 = 1004.8 = 1005 cm^3

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen