An archery target is shown. the length of a side of the inner square is 4 m and the length of a side of the outer square is 7 m if an arrow hits the target at random, what is the probability that it hits the inner square? round to the nearest percent.

This is the concept of the probability and statistics. To get the probability of hitting the inner circle we proceed as follows;
P(inner square)=[area of inner circle]/[area of outer square]
area of inner square will be:
Area=length*width
Area=4*4=16 m^2
Area of outer square:
Area=7*7=49 m^2
thus;
P(hitting inner square)=16/49=0.3265=32.65%