Suppose that the length of a certain rectangular is 1 meter more than 5 times it width. the perimeter of rectangular is 98 meters. find the length and width

Let breadth(b) of rectangular be x
Then length(l) = 5x + 1
We have : perimeter(p) =2(l+b)
Or, p = 2 (5x+1+x)
p = 2 (6x+ 1)
p = 12x + 2
Given that p= 98 m
98=12x+2 i.e. x= 8
So breadth b= 8m and length l =5*8+1= 41m

It is 198,87032,750 + 375 = 33145 so, we take the 6% and we make it a decimal (0.6) and multiply that, then that is your answer