Read the proof.
given: aeec; bddc
prove: △aec ~ △bdc

statement reason
1. aeec; bddc 1. given
2. ∠aec is a rt. ∠; ∠bdc is a rt. ∠ 2. definition of perpendicular
3. ∠aec ≅ ∠bdc 3. all right angles are congruent
4. ? 4. reflexive property
5. △aec ~ △bdc 5. aa similarity theorem
what is the missing statement in step 4?
a.∠ace ≅ ∠ace
b.∠eab ≅ ∠dbc
c.∠eac ≅ ∠eac
d.∠cbd ≅ ∠dbc

Asap (explain how you got it as well for brainliest)i tried 1: 2 and 2: 3 and they were wrong. picture of figure: in the figure below, the segment is parallel to one side of the triangle. the ratio of 12 to y is1: 21: 31: 42: 3

Consider the function y = f(x)=3^x the values of f(1/2) and f(1/4). rounded to the nearest hundredth, are__and__ respectively

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane