Write an equation of a line that passes through the point (7, 3) and is parallel to the line y = negative 2 over 3 x + 3. (5 points)

y = 3 over 2 x − 3
y = 3 over 2 x + 3
y = negative 2 over 3 x + 23 over 3
y = negative 2 over 3 x − 23 over 3

m!

i got y-3= -2/3 (x-7)

answer:

step-by-step explanation:

given: equation of line

slope form of the line y=mx+c

comparing with above equation

let the equation of line in form y=mx+a

since the lines are parallel their slopes are equal

therefore,

and this line passes through (7,3) point

so,

putting back in equation of line  

is the required equation.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation: