Suppose an isosceles triangle abc has a = 45° and b = c = 3. what is the length of a2? a. 12.73 b. 5.27 c. 2.30 d. 30.73

Given that A=45 and b=c=3, to get the value of a we use the cosine rule;
a^2=b^2+c^2-2bcCosA
thus;
a^2=3^2+3^2-2*3*3cos45
a^2=9+9-18cos 45
a^2=18-18cos45
a^2=5.2721
thus;
a=sqrt5.2721
a=2.296-=2.3
The answer is C. 2.3