Find two supplementary angles such that the smaller is 30 degrees more than one-half the larger

100° and 80°

working:

supplementary angles = angle + angle = 180°

let the larger angle be x
smaller angle = (x/2) + 30

x + ((x/2) + 30) = 180°
(2x + x + 60) / 2 = 180°
3x + 60 = 360°
3x = 300°
x = 100°

Therefore the larger angle is 100°

smaller angle
= (100° / 2) + 30°
= 80°

Therefore, the two supplementary angles are 100° and 80°

1.5 pounds because you put 9over 6 and then divide by 6

The answer should be 5.