What is log6^e f rewritten using the power property?
elog6f
flog6e
log6(e×f)
log6(e+f)

The expression , equivalent log function will be

According to the law of logarithm given as:

From the law, we can see that the power of the logarithm is taken to the back of log function.

For the expression , the equivalent log function will be

Learn more on logarithm power here: link

$12. that is my answer.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752