What is the solution to the equation below? log64x^2-log6x=2
x=1/2
x=3/2
x=3
x=9

First, we need to put the conditions: 4x^2 >0 which is obviously true
x>0
We will apply the formulas:
loga(x) - loga(y) = loga(x/y)
and
if loga(x)=b then x = a^b

log6(4x^2)-log6(x)=2
Applying first formula
log6(4x^2/x) = 2
log6(4x) =2

Applying the second formula:
4x = 36
x=9 

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm