Anyone
which functions have real zeros at 1 and 4? check all that apply.
a f(x) = x^2 + x + 4
b f(x) = x^2 – 5x + 4
c f(x) = x^2 + 3x – 4
d f(x) = –2x^2 + 10x – 8
e f(x) = –4x^2 – 16x – 1

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches