What is the additive inverse of the complex number 13 – 2i?

-13+2i

Explanation:

We have been given with the a complex number 13-2i

The additive inverse of complex number is -(a+ib)

Complex number general representation is a+ib where a and b are real numbers.

Here we have a complex number 13-2i  so a=13 and b=-2i

So, additive inverse will be -(13-2i) after simplifying we will get -13+2i

Therefore additive inverse of complex number is -13+2i

step-by-step explanation:

ιт ιѕ (9χ^5+10)(81χ^10-90χ^5+100)

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ уσυ συт тσ∂α